(4/x+2)+(1/x-2)=(19/x^2-4)

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Solution for (4/x+2)+(1/x-2)=(19/x^2-4) equation: 



(4/x+2)+(1/x-2)=(19/x^2-4)

We move all terms to the left:

(4/x+2)+(1/x-2)-((19/x^2-4))=0



Domain of the equation: x+2)!=0

x∈R





Domain of the equation: x-2)!=0

x∈R





Domain of the equation: x^2-4))!=0

x∈R



We get rid of parentheses

4/x+1/x-((19/x^2-4))+2-2=0

We calculate fractions

We do not support expression: x^3

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